tag:blogger.com,1999:blog-8303906221917588052.post5524218253773406567..comments2020-05-05T02:53:30.558-04:00Comments on Author Amok: Probability ... none.Author Amokhttp://www.blogger.com/profile/13636391982938592789noreply@blogger.comBlogger7125tag:blogger.com,1999:blog-8303906221917588052.post-75795011809617104142015-09-07T04:07:46.566-04:002015-09-07T04:07:46.566-04:00Glad you got the correct answers! It's my faul...Glad you got the correct answers! It's my fault that Dash divided it by 6, I expect, because I thought the number was awfully big. I thought you wanted it for something to happen in your book and it would never get around to happening if it took that many days! Tabathahttps://www.blogger.com/profile/14367572663591077922noreply@blogger.comtag:blogger.com,1999:blog-8303906221917588052.post-14980738681472477602015-09-06T17:19:20.594-04:002015-09-06T17:19:20.594-04:00Thanks, everyone. I'm amazed by how many peopl...Thanks, everyone. I'm amazed by how many people were up for this challenge.<br /><br />"Basic" problem: 10,626 seems to be the winner. My follow up question is this: Is this number the number of possible combinations for *all* the students? If so, how often would one particular grouping of four meet during those 10,626 times?<br /><br />Challenge problem: I have a follow up question that may turn some of the information into a red herring. If you are a girl and one of the other girls in the class was your best friend, how often could you expect to eat a meal with her?<br /><br />Would it help to assign the girl and her friend names? Girl X and Girl Y -- keeping it mathy.Author Amokhttps://www.blogger.com/profile/13636391982938592789noreply@blogger.comtag:blogger.com,1999:blog-8303906221917588052.post-58504282069476861652015-09-06T13:03:16.548-04:002015-09-06T13:03:16.548-04:0010,626 and 4,356 are correct. Not sure why Tabatha...10,626 and 4,356 are correct. Not sure why Tabatha is dividing by 6. There are still as many possible combinations no matter how many tables there are. It's a basic Bayesian combination. (24 choose 6, (12 choose 2) squared)Sue Poduskahttps://www.blogger.com/profile/05743846796996415379noreply@blogger.comtag:blogger.com,1999:blog-8303906221917588052.post-13082117495535898542015-09-06T11:49:27.059-04:002015-09-06T11:49:27.059-04:00If this were my WIP, I would b .doing what you'...If this were my WIP, I would b .doing what you're doing: asking for help. This is not my strength. It's sounds like you have answers.Jonehttps://www.blogger.com/profile/04299647754479967070noreply@blogger.comtag:blogger.com,1999:blog-8303906221917588052.post-74545806146007315492015-09-06T11:35:01.571-04:002015-09-06T11:35:01.571-04:00I got a slightly different answer, including not c...I got a slightly different answer, including not counting pairs in a math problem that are the same - AB or BA for example. There are 66 pair possibilities with just the boys and/or the girls. Combining them (as twosomes) would create 2,145 days of different foursomes. I'll keep checking, but have to go out. Linda Bhttps://www.blogger.com/profile/14983144542632353870noreply@blogger.comtag:blogger.com,1999:blog-8303906221917588052.post-59259223628792462402015-09-06T11:16:02.530-04:002015-09-06T11:16:02.530-04:00This was taken off a calculator where the answer w...This was taken off a calculator where the answer was given. I believe that you are looking at 10626 different 'groups' before you can sit with all the students in all possible groups. (I got that number off a lotto website. I didn't do the math myself.<br /><br />Directions: Apply the combination formula to solve the problems below.<br />Problem 1) In a class of 10 students, how many ways can a club of 4 students be arranged? <br /> Answer <br />Combination Formula Applied<br />210<br /><br />http://www.mathwarehouse.com/probability/combination.php<br /><br />This was a fun way to get my brain working in the morning but without a scientific calculator I'm pretty useless.<br />June Smallshttps://www.blogger.com/profile/00344423860787737601noreply@blogger.comtag:blogger.com,1999:blog-8303906221917588052.post-58780818642869760762015-09-06T11:14:33.375-04:002015-09-06T11:14:33.375-04:00Dash is not sure, but he thinks it is 1,771 days f...Dash is not sure, but he thinks it is 1,771 days for the original question. (There are 10,626 possible foursomes, divided by six is 1,771.) For the challenge question, he thinks it's only 726 days. (There are 4,356 possible foursomes.)Tabathahttps://www.blogger.com/profile/14367572663591077922noreply@blogger.com